EAL, part of the Enginuity Group
Engineering Maths Skills ProgrammeLearner workbook · Module 05
GCSE Maths in Engineering · Module 05

Sizing a
hydraulic tank

A hydraulic power pack needs a reservoir big enough to let the oil cool and settle, small enough to fit the bay, and cheap enough to build. You will use volume, surface area and density to find one that does all three.

Drawing no.GM-05/TANK
TopicsG16 · G17 · R11 · N13
Target grades4–8
Duration50–60 min · 12 marks
01

The job

Read the spec like an engineer

The power pack driving Ashfield's press needs a fabricated steel oil reservoir. It is an open-topped box with a bolted lid, 0.45 m wide, with the length and height for you to choose.

  • The pump moves 45 litres per minute, and the tank must hold at least three times that
  • Add 10% on top for an air gap above the oil — so 150 litres minimum
  • The bay allows a maximum tank length of 0.90 m
  • Mild steel plate in 3, 4 or 5 mm: density 7850 kg/m³, priced at £22, £28 and £34 per m²
  • Budget for plate: £45. Hydraulic oil has a density of 870 kg/m³

Your question: what length and height give you 150 litres or more without running out of floor space or money?

02

Explore the drawing

Drag the corner grip to resize
Drag the corner grip on the tank to stretch it in both directions at once.
Thicker plate is stiffer but heavier and dearer per square metre.
3 mm
Capacity162 L
Plate area1.85 m²
Mass of steel43 kg
Plate cost£41

Stretch the tank by its corner and watch both gauges. Capacity grows with three dimensions but plate area with only two, so a bigger tank is always better value per litre — it is the bay and the budget that stop you, never the geometry.

03

Worked solution

Open one step at a time

Take the 0.80 m long, 0.45 m high tank and check it properly.

The rule of thumb is that a reservoir holds three minutes' worth of pump flow, so the oil has time to shed heat and let air bubbles rise out.

3 × 45 = 135 litres of oil
135 × 1.10 = 148.5 → 150 litres of tank

The 10% is the air gap above the oil. Fill a hydraulic tank to the brim and it vents oil across the workshop floor the moment it warms up.

V = 0.80 × 0.45 × 0.45 = 0.162 m³
0.162 × 1000 = 162 litres

162 ≥ 150, so the capacity rule is satisfied. Passes.

Remember this one
1 m³ = 1000 litres. It comes up constantly in engineering questions and it is worth knowing cold rather than deriving it under exam pressure.

A closed box has three pairs of identical faces.

SA = 2(LW + LH + WH)
SA = 2(0.80×0.45 + 0.80×0.45 + 0.45×0.45)
SA = 2(0.36 + 0.36 + 0.2025) = 2 × 0.9225 = 1.845 m²
Examiner note
Write the three products down separately before doubling. Almost every lost mark on surface area comes from missing a pair of faces, and a written list makes that impossible.

The plate is 3 mm thick, so its volume is area × thickness — but the thickness must be in metres.

3 mm = 0.003 m
volume = 1.845 × 0.003 = 0.005535 m³
mass = 0.005535 × 7850 = 43.5 kg

Worth knowing before you plan how to lift it onto the machine.

plate cost = 1.845 × 22 = £40.59 ✓ under £45
oil filled to 90%: 0.162 × 0.9 = 0.1458 m³
oil mass = 0.1458 × 870 = 126.8 kg

Full tank, oil and steel together: about 170 kg. That is a floor-loading question as well as a maths one.

Try 0.35 m high: capacity falls to 126 litres and the tank fails the cooling rule. Stretch the length to 1.0 m to recover it and you break the 0.90 m bay limit instead.

volume ∝ L × W × H (three dimensions)
plate ∝ two dimensions at a time

Because volume grows faster than surface area, a bigger tank is always better value per litre. The limits that stop you are the bay and the budget, never the geometry.

04

Your turn

Answers checked instantly
Q1Volume and unit conversion2 marks

A tank measures 0.75 m by 0.40 m by 0.50 m. Work out its capacity in litres.

litres
Q2Density2 marks

That tank is filled to 90% with oil of density 870 kg/m³. Work out the mass of the oil, to 1 decimal place.

kg
Q3Surface area of a cuboid3 marks

Work out the total surface area of that closed tank, to 2 decimal places.

05

Exam-style question

Full mark scheme
Q4Cylinders, volume and density5 marks

An alternative reservoir is a closed cylinder of diameter 0.60 m and height 0.80 m, rolled from the same 3 mm plate (density 7850 kg/m³).

Work out its capacity in litres, to the nearest litre. The mark scheme also asks for the mass of the plate, so find that too.

litres

Mark scheme — 5 marks

  1. Radius = 0.60 ÷ 2 = 0.30 m B1
  2. V = πr²h = π × 0.30² × 0.80 = 0.2262 m³ M1 A1
  3. Capacity = 0.2262 × 1000 = 226 litres A1
  4. SA = 2πr² + 2πrh = 0.5655 + 1.5080 = 2.0735 m²; mass = 2.0735 × 0.003 × 7850 = 48.8 kg A1

Accepted answer: 226 litres. Using the diameter in place of the radius is the classic error and it makes the answer four times too big — if your capacity came out near 900 litres, that is what happened. Halve the diameter before anything else touches the calculator.

Marks scored0/12
Not started
EAL, part of the Enginuity Group

Produced for EAL engineering learners.
Maps to GCSE Mathematics (9–1) — volume and surface area of prisms and cylinders, and density.