EAL, part of the Enginuity Group
Engineering Maths Skills ProgrammeLearner workbook · Module 02
GCSE Maths in Engineering · Module 02

Batching a
concrete base

A machine foundation is only as good as the mix poured into it. You will use ratio, volume and percentages to work out exactly how much concrete to order, how much cement it swallows, and whether the job clears its budget.

Drawing no.GM-02/CONC
TopicsR5 · R8 · G16 · N12
Target grades4–7 (stretch to 9)
Duration45–60 min · 12 marks
01

The job

Read the spec like an engineer

Ashfield Engineering is casting a reinforced concrete base for a new 40-tonne press. The base is a rectangular slab, 3.00 m long by 2.00 m wide, and its depth is yours to decide.

  • Wet concrete has a density of 2400 kg per m³
  • Slab depth must be at least 0.40 m — to carry the press footing
  • The press data sheet demands grade C25 or stronger
  • Order 5% extra to cover spillage and over-dig
  • Client's budget for concrete: £350

Your question: which mix, and what depth, satisfies the strength rule, the depth rule and the budget all at once?

02

Explore the drawing

Drag, drop and tap — then calculate
Drag sacks from the rack into the mixer drum. Equivalent ratios count — 2:4:8 is still a 1:2:4 mix.
Click the depth staff beside the slab to set it, or nudge below.
0.45 m
Volume of slab2.70 m³
Cement needed926 kg
25 kg bags38
Concrete cost£326

Build the mix by dragging sacks into the drum and set the depth on the staff gauge. Equivalent ratios behave identically, which is the whole point of ratio: 2:4:8 and 1:2:4 are the same concrete.

03

Worked solution

Open one step at a time

Take the 0.45 m deep slab in a 1:2:4 mix and check it properly.

The slab is a cuboid, so volume is length × width × depth.

V = 3.00 × 2.00 × 0.45 = 2.70 m³

Keep the units consistent. All three measurements are already in metres, so the answer is in cubic metres.

mass = volume × density = 2.70 × 2400 = 6480 kg
Examiner note
Density questions are marked on the relationship, not the number. Writing mass = volume × density before you substitute banks the method mark.

A 1:2:4 mix has 1 + 2 + 4 = 7 parts in total.

one part = 6480 ÷ 7 = 925.71 kg
cement = 1 × 925.71 = 925.7 kg
sand = 2 × 925.71 = 1851.4 kg
aggregate = 4 × 925.71 = 3702.9 kg

Check: 925.7 + 1851.4 + 3702.9 = 6480 kg. The parts must add back to the whole.

925.71 ÷ 25 = 37.03 bags

You cannot buy 0.03 of a bag, so you round up to 38 bags.

Watch out
This is the classic trap. The calculator says 37.03 and the instinct is to write 37. Ask yourself what the number is for: run short of cement and the pour stops.
order = 2.70 × 1.05 = 2.835 m³
cost = 2.835 × 115 = £326.03

£326.03 against a £350 budget — approved, with £23.97 in hand.

Grade 7–9 move
Use the multiplier × 1.05 in a single step rather than finding 5% and adding it on. Fewer keystrokes, fewer slips.

Go shallower than 0.40 m and the footing is rejected. Go past roughly 0.48 m and the ready-mix bill breaks the budget.

depth rule → d ≥ 0.40 m
budget rule → d ≤ 0.48 m

Choose the richer C30 mix and that ceiling drops to about 0.43 m, because you are paying £128 rather than £115 for every cubic metre. Stronger concrete is not free.

04

Your turn

Answers checked instantly
Q1Volume of a prism2 marks

A different base measures 2.40 m by 1.80 m by 0.50 m deep. Work out its volume in cubic metres.

Q2Sharing in a ratio2 marks

That base is poured in a 1:2:4 mix. Using a density of 2400 kg/m³, work out the mass of cement needed, to 1 decimal place.

kg
Q3Rounding in context3 marks

Cement is delivered in 25 kg bags. How many whole bags must be ordered for that base?

bags
05

Exam-style question

Full mark scheme
Q4Multi-step problem solving5 marks

A larger base measures 3.50 m by 2.20 m by 0.40 m deep and is poured in a 1:1.5:3 mix costing £128 per m³. Concrete is ordered with 5% extra for waste and has a density of 2400 kg/m³.

Work out the total cost of the concrete, to the nearest pound. The mark scheme also asks for the mass of cement, so find that too.

£

Mark scheme — 5 marks

  1. Volume = 3.50 × 2.20 × 0.40 = 3.08 m³ M1 A1
  2. Volume ordered = 3.08 × 1.05 = 3.234 m³ M1
  3. Cost = 3.234 × 128 = £413.95 = £414 A1
  4. Cement: total mass = 3.08 × 2400 = 7392 kg; parts = 1 + 1.5 + 3 = 5.5; cement = 7392 ÷ 5.5 = 1344 kg A1

Accepted answer: £414. The commonest lost mark is applying the 5% to the cost instead of the volume — here it happens to give the same figure, but it will not when a fixed delivery charge is added, so build the habit now.

Marks scored0/12
Not started
EAL, part of the Enginuity Group

Produced for EAL engineering learners.
Maps to GCSE Mathematics (9–1) — ratio and proportion, volume of prisms, and percentages.